leetcode 778. Swim in Rising Water
题目描述
On an N x N grid
, each square grid[i][j]
represents the elevation at that
point (i,j)
.
Now rain starts to fall. At time t
, the depth of the water everywhere ist
. You can swim from a square to another 4-directionally adjacent square if
and only if the elevation of both squares individually are at most t
. You
can swim infinite distance in zero time. Of course, you must stay within the
boundaries of the grid during your swim.
You start at the top left square (0, 0)
. What is the least time until you
can reach the bottom right square (N-1, N-1)
?
Example 1:
Input: [[0,2],[1,3]]
Output: 3
Explanation:
At time 0, you are in grid location (0, 0).
You cannot go anywhere else because 4-directionally adjacent neighbors have a higher elevation than t = 0.
You cannot reach point (1, 1) until time 3.
When the depth of water is 3, we can swim anywhere inside the grid.
Example 2:
Input: [[0,1,2,3,4],[24,23,22,21,5],[12,13,14,15,16],[11,17,18,19,20],[10,9,8,7,6]]
Output: 16
Explanation:
**0 1 2 3 4**
24 23 22 21 **5**
**12 13 14 15 16**
**11** 17 18 19 20
**10 9 8 7 6**
The final route is marked in bold.
We need to wait until time 16 so that (0, 0) and (4, 4) are connected.
Note:
2 <= N <= 50
.- grid[i][j] is a permutation of [0, …, N*N - 1].
Tags: Binary Search, Heap, Depth-first Search, Union Find
Difficulty: Hard